Re: xsl list breakdown?

Michael wrote:
> How would I take a <list><item/><item/><item/></list> and say break it
> down into a table with 2 elements per row? Thanks.

Select the items that start each row.
Generate a row for each of those.
The first cell's content is based on the current item;
tje second cell's content is calculated relative to the current item.
If there's no content to fill in a cell, use '&#160;'.

If you want to do colspan tricks instead, you just have to think
of a way to test that the current node is not the last in the row, and
that it doesn't have following siblings. Then you can generate a
colspan attribute with xsl:attribute, and give it a value that is
(max # of columns - 1) - position() ... at least, that's one way to
go about it.

Have you skimmed through the FAQ at http://www.dpawson.co.uk/ ?
Many examples there...

   - Mike
____________________________________________________________________________
  mike j. brown                   |  xml/xslt: http://skew.org/xml/
  denver/boulder, colorado, usa   |  resume: http://skew.org/~mike/resume/

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