Re: XML to XML transformation

I need to transform one XML to another XML. Some of the elements in the
source XML has an attribute xsi:type and the value is a java class name. In
the output xml I want to remove this attribute and change the name of the
element to something based on the java class name.

T:\ftemp>type subramanian.xml
 <javaobject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:type="java:a.b.c"
       attr1="123">
   <a-subelement>Test</a-subelement>
   <!--end of test-->
  </javaobject>

T:\ftemp>type subramanian.xsl
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
                exclude-result-prefixes="xsi"
                version="1.0">

<xsl:template match="*[@xsi:type]"><!--elements of an XS type-->
  <xsl:element name="{translate( substring-after( @xsi:type, 'java:' ),
                                 '.', '' )}">
    <xsl:apply-templates select="@*|node()"/>
  </xsl:element>
</xsl:template>

<xsl:template match="*"> <!--synthesize element with the input name-->
  <xsl:element name="{name(.)}" namespace="{namespace-uri(.)}">
    <xsl:apply-templates select="@*|node()"/>
  </xsl:element>
</xsl:template>

<xsl:template match="@*"> <!--synthesize attribute with theinput name-->
  <xsl:attribute name="{name(.)}" namespace="{namespace-uri(.)}">
    <xsl:value-of select="."/>
  </xsl:attribute>
</xsl:template>

<xsl:template match="comment()|processing-instruction()">
  <xsl:copy/>
</xsl:template>

T:\ftemp>xt subramanian.xml subramanian.xsl
<?xml version="1.0" encoding="utf-8"?>
<abc attr1="123">
   <a-subelement>Test</a-subelement>
   <!--end of test-->
  </abc>
T:\ftemp>

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