Returning the file name of the input file
Hello, does anybody if the following is possible: I want to use the name of the inputfile in the outputfile. So if I want to transform the file c:\temp\test.xml, I want to get in my output c:\temp\test.xml. I am afraid there is no method to do this, but if anybody knows a solution I will be very thankfull for that. kind regards, Ismaël XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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