Re: does an element have a unique id?, and a problem t

Hi Thomas,

> 1) how to specifiy parameter in XSLT in Cocoon so that it works also
> when no parameter is given; I've added:
>
>   <map:match pattern="*/*-*">
>     <map:generate src="content/{1}/{2}.xml"/>
>     <map:transform src="transforms/inners.xsl">
>         <map:parameter name="param" value="{3}"/>
>         <map:parameter name="css-stylesheet" value="default.css"/>
>     </map:transform>
>     <map:serialize type="html"/>
>   </map:match>
>
> so, it works when there is a "*/*-1" but comes to an error when
> typing "*/*", however I would like to declare in XSL that if there
> is no param ("-*"), use the first <content/>. I don't know how to
> make it work this way. (???)

I'm a little rusty on Cocoon, but what about having a separate match
like:

  <map:match pattern="*/*">
    <map:generate src="content/{1}/{2}.xml" />
    <map:transform src="transforms/inners.xsl">
      <map:parameter name="param" value="1" />
      <map:parameter name="css-stylesheet" value="default.css" />
    </map:transform>
  </map:match>

Put this *after* the match you already have, as it's a more general
pattern and Cocoon uses the first available match.
  
Or perhaps you can use the regexp URI matcher rather than the wildcard
URI matcher?
  
> 2) I've tried to use the postion() for specifing the parameter to
> render with the special formating as follows:
>
>     <xsl:for-each select = "content[position() != $firstcontent]">
>      <xsl:if test = "position() mod 2 = 0">
>      <p/><h3><xsl:value-of select="header1"/></h3>
>      <xsl:value-of select="concat(substring-before(para, '.'),
> '.')"/>&#160;<a href="{position()}" class="navigators">&#x00BB;</a>
>       </xsl:if>
>  </xsl:for-each>
>
> but in case of $firstcontent=2 the for-each will not list it, and
> position will start from 1, so position() doesn't show the original
> listed id/position as it is in the XML doc. Beyond adding an
> attribute to the element in the XML for specifing a unique
> identifier, is there something else how I can find out the original
> XML content position number?

You could use xsl:number to give you the position, or calculate it by
counting the number of preceding sibling content elements there are
and adding 1:

  count(preceding-sibling::content) + 1

> What's make it hard, so that a simple for-each for only "content"
> won't work, is that I have 2 columns, and if I use only the content
> for-each list and display every odd and even position(), than incase
> of a $firstcontent=2 and having 5 <content/> the first column will
> have pos:1,3,5 and the second column will have pos: 4, but what I'd
> like to show is that every second <content/> goes to the same column
> => column1 will have: pos:1, 4 and column2 will have pos: 3,5.

Sure. I think that the above will work fine if you use the count() to
give you the number-amongst-all-content elements and position() to
give you the position to determine where it should go in the table.

Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


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