RE: XPath selection using //

I am a little unsure of what you are trying to do and your xml
sample is not well formed but here goes;

This template will produce the result you are after;

 <xsl:template match="m">
   Attribute a of the following m is: <xsl:value-of
select="following::m/@a"/>
 </xsl:template>

The 'following-sibling' axes will only match nodes of the same depth 
of the xml document. 

Cheers,
Ben


-----Original Message-----
From: Filipe Correia [mailto:filipe.correia@xxxxxxxxxxxxxxx]
Sent: 17 July 2002 15:11
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  XPath selection using //



  Hi,

Here's a tree wich is a part of my xml document:

<b>
  <m a="attribute">
    text text text
    <t>
      <r>
        <d>more text</d>
      <r/>
    </t>
  </m>
  <t>
    <r>
      <d/>
      <d><m a="attribute">text</m></d>
    <r/>
  </t>
  <m/>
  text
</b>

what I want to do is to evaluate only the
contents of the "m" elements. For each "m"
element I also need to output the next "m"'s
"a" atribute.
Everything else should be ignored.

In the stylesheet that I use I'm applying the
respective templates like this:

   ...

   <xsl:apply-templates select="b//m"/>

   ...

 using the following template to apply
 templates to all descendants of the
 current "m" node and to get the next "m"'s
 "a" atribute:

   <xsl:template match="m">
	<xsl:apply-templates/>
      Atribute a of the following m is: 
      <xsl:value-of
select="ancestor::*[parent::b]/following-sibling::node()//m/@a"/>
   </xsl:template>

 but getting the next "m"'s "a" atribute is
 not working as I expected...

 Any idea on what I may be doing wrong?


     Thanks in advance,

       Filipe


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