Re: XPath iteration?

>       /Root/SomeNode[position()!=position(/Root/SomeNode)]
nodes don't have a position() property, only a position in the current
node list, so teh same node will have different positions depending on
how it is accessed (eg it always has position()=1 if accessed by ..
)

so position(/Root/SomeNode) is a syntax error, I can't actually guess
what you wanted your entire expression to mean, but usually when people
try position(...) they want something like
1+count(/root/SomeNode/preceding-sibling::*)
David

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