AW: reverse sorting

Hi,

nest a xsl:sort Element in xsl:for-each and use position() as expression for
sorting.

<xsl:for-each
select="PROCESS_DESCRIPTION_SHEET/PAGE_HEADER/PATH_LIST/PATH_ELEM">
    <xsl:sort select="position()" order="descending"/>
    <xsl:value-of select="."/>
</xsl:for-each>


Thomas
Orientation in Objects,
http://www.oio.de


> -----Ursprüngliche Nachricht-----
> Von: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]Im Auftrag von sascha
> Gesendet: Dienstag, 30. Juli 2002 11:35
> An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Betreff:  reverse sorting
>
>
> Hi,
>
> is it possible to sort this input in reverse order?
>
> <PATH_LIST>
>    <PATH_ELEM>last entry</PATH_ELEM>
>    <PATH_ELEM>Operartive Prozesse</PATH_ELEM>
>   <PATH_ELEM>Angebot, Verhandlung, Vertragsabschluss</PATH_ELEM>
>   <PATH_ELEM>first entry</PATH_ELEM>
> </PATH_LIST>
>
> so that the output looks like
>
>
> - first entry
> - Angebot, Verhandlung, Vertragsabschluss
> - Operartive Prozesse
> - last entry
>
>
> actually my template looks like this:
>
> ..
> <xsl:for-each
> select="PROCESS_DESCRIPTION_SHEET/PAGE_HEADER/PATH_LIST/PATH_ELEM">
>     <xsl:value-of select="."/><fo:block/>
> </xsl:for-each>
>
> ..
>
> thanks again,
> sascha
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list