RE: xsl:include href attribute

you can't use variables within <xsl:include>... I suspect you will want
to write a custom URI resolver and set the base that way...

how are you currently applying the transform? (Saxon in java?)

 



-----Original Message-----
From: Nathan Shaw [mailto:n8_shaw@xxxxxxxxx]
Sent: 16 July 2002 17:41
To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
Subject:  xsl:include href attribute


Can someone help me out as to where I am going wrong
here? I am trying to use a var as the value of the
href attribute of xsl:include.

----------------------------------------------------------
<!-- change to real URL when moving to production -->
<xsl:variable name="includePath"
select="'http://xxx.xxx.xxx.xxx/dir/'" />
<xsl:variable name="getFileInfoPath"
select="concat($includePath,'common/getFileInfo.xsl')"
/>

<!-- get the xml file's name and parent directory:
$FileName, $FileDir -->
<xsl:include href="{$getFileInfoPath}" />

However, when I try to parse an xml doc, for some
reason, Saxon is trying to use the base url and tack
on the var, so it ends up trying to find the included
xslt at e:\wwwroot\dir\{$getFileInfoPath} instead of
expanding the var and going to
'http://xxx.xxx.xxx.xxx/dir/common/getFileInfo.xsl'

If I hard-code the URI in there as
'http://xxx.xxx.xxx.xxx/dir/common/getFileInfo.xsl,'
it finds it perfectly fine.

What am I missing?

[I am a digester, so a cc is appreciated.]

--n

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