Re: XSLTC key() with for-each Problem

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Subject: Re: XSLTC key() with for-each Problem
From: Joerg Heinicke <joerg.heinicke@xxxxxx>
Date: Fri, 12 Jul 2002 23:16:55 +0200

Is there any other way to force the key() function to refer to the nodes in $old_file? The name of the old file is being passed into the stylesheet as a parameter, so I don't believe it can be directly referenced in <xsl:key>.

<xsl:key> works per XML tree, you don't specify a special one (or a document) in the key-declaration. With your <xsl:for-each select="$oldfile"> you only change the context document for the key to work on.

So there is no work around if there is really a bug in XSLTC. Either you use the inefficient method or must wait until the bug is fixed.

Joerg

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

Current Thread
XSLTC key() with for-each Problem Troy Thibodeaux - Fri, 12 Jul 2002 15:57:01 -0400 (EDT) Joerg Heinicke - Fri, 12 Jul 2002 17:16:33 -0400 (EDT) <= Troy Thibodeaux - Fri, 12 Jul 2002 18:13:01 -0400 (EDT) Michael Kay - Sat, 13 Jul 2002 08:09:48 -0400 (EDT)

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XSLTC key() with for-each Pro, Troy Thibodeaux	Thread	Re: XSLTC key() with for-each, Troy Thibodeaux
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