RE: RE: merging generic elements in a parent-child rel

thanks Dimitre!
But is it possible to apply a unique stylesheet to the originial xml I've
posted? Or I need to do this in two steps?

this is the original one
<root>
 	<Persona id="abc" idCountry="1"/>
 	<Persona id="abcd" idCountry="1"/>
 	<b id="b1" idPersona="abc"/>
 	<b id="b2" idPersona="abc"/>
 	<b id="b3" idPersona="abcd"/>
	<c id="c1" idb="b1"/>
</root>

and this is my styleheet which do the original job. How do you insert the
Muenchian method here?

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
	<xsl:param name="TopElement" select="'Persona'" />
<xsl:template match="root">
   <root>
     <xsl:apply-templates select="/*/*[name() = $TopElement]"/>
   </root>
</xsl:template>

<xsl:template match="*">

   <xsl:element name="{name()}">
   <xsl:variable name="currentTag" select="name()"/>
     <xsl:copy-of select="@*"/>
     <xsl:apply-templates
select="../*[@*[name()=concat('id',$currentTag)]=current()/@id]"/>
   </xsl:element>

</xsl:template>
</xsl:stylesheet>

thanks a lot!
Matias

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Dimitre
> Novatchev
> Sent: jueves, 27 de junio de 2002 17:26
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: RE:  merging generic elements in a parent-child
> relationship Part II
>
>
> --- "Matias Woloski" <woloski at sion dot com> wrote:
>
> >
> > I've solved both problems!
> > I did this for the param problem
> > <xsl:apply-templates select="//*[name()=$TopElement]"/>
> > so this will choose all the elements whose name is stored in
> > TopElement
> > and the id problem
> > I added a variable currentTag
> > <xsl:variable name="currentTag" select="name()"/>
> > ...
> > <xsl:apply-templates
> > select="../*[@*[name()=concat('id',$currentTag)]=current()/@id]"/>
> >
> > But I have a question now...
> > I have the XML transformed like this
> >
> > <?xml version="1.0" encoding="UTF-8"?>
> > <root>
> > 	<Persona id="abc" idCountry="1">
> > 		<b id="b1" idPersona="abc"></b>
> > 		<b id="b2" idPersona="abc"></b>
> > 		<c id="c1" idb="b1" idPersona="abc">
> > 		</c>
> > 	</Persona>
> > 	<Persona id="abcd" idCountry="1">
> > 		<b id="b3" idPersona="abcd">
> > 		</b>
> > 	</Persona>
> > </root>
> >
> > I want to wrap each collection of elements into other element. Like
> > this
> >
> > <?xml version="1.0" encoding="UTF-8"?>
> > <root>
> > 	<PersonaGroup>
> > 		<Persona id="abc" idCountry="1">
> > 			<bGroup>
> > 				<b id="b1" idPersona="abc"></b>
> > 				<b id="b2" idPersona="abc"></b>
> > 			</bGroup>
> > 			<cGroup>
> > 				<c id="c1" idb="b1" idPersona="abc"></c>
> > 			</cGroup>
> > 		</Persona>
> > 		<Persona id="abcd" idCountry="1">
> > 			<bGroup>
> > 				<b id="b3" idPersona="abcd"></b>
> > 			</bGroup>
> > 		</Persona>
> > 	</PersonaGroup>
> > </root>
> >
> > thanks!
> >
> > ps: Dimitre thanks for answering... actually I've already solved it
> > in
> > a
> > similar way... do you know the last question?
>
>
> Yes, this is a grouping problem. Bellow I use the Muenchian method:
>
> <xsl:stylesheet version="1.0"
>  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
>  <xsl:key name="kPers-Names" match="Persona/*"
>           use="concat(generate-id(..), '||', name())"/>
>
>   <xsl:strip-space elements="*"/>
>
>   <xsl:output omit-xml-declaration="yes" indent="yes"/>
>
>   <xsl:template match="/">
>     <root>
>       <xsl:apply-templates/>
>     </root>
>   </xsl:template>
>
>   <xsl:template match="Persona">
>     <xsl:copy>
>       <xsl:copy-of select="namespace::* | @*"/>
>       <xsl:for-each select="*[generate-id()
>                              =
>                               generate-id(key('kPers-Names',
>                                                concat(generate-id(..),
>                                                       '||',
>                                                        name()
>                                                        )
>                                                )[1])]">
>
>         <xsl:element name="{name()}Group">
>           <xsl:copy-of select="key('kPers-Names',
>                                     concat(generate-id(..),
>                                            '||',
>                                             name()
>                                            )
>                                     )"/>
>         </xsl:element>
>       </xsl:for-each>
>     </xsl:copy>
>   </xsl:template>
> </xsl:stylesheet>
>
> When applied to your original source xml:
>
> <root>
> 	<Persona id="abc" idCountry="1">
> 		<b id="b1" idPersona="abc"></b>
> 		<b id="b2" idPersona="abc"></b>
> 		<c id="c1" idb="b1" idPersona="abc">
> 		</c>
> 	</Persona>
> 	<Persona id="abcd" idCountry="1">
> 		<b id="b3" idPersona="abcd">
> 		</b>
> 	</Persona>
> </root>
>
> The result of the transformation is exactly as wanted:
>
> <root>
>    <Persona id="abc" idCountry="1">
>       <bGroup>
>          <b id="b1" idPersona="abc"/>
>          <b id="b2" idPersona="abc"/>
>       </bGroup>
>       <cGroup>
>          <c id="c1" idb="b1" idPersona="abc"/>
>       </cGroup>
>    </Persona>
>    <Persona id="abcd" idCountry="1">
>       <bGroup>
>          <b id="b3" idPersona="abcd"/>
>       </bGroup>
>    </Persona>
> </root>
>
>
> Cheers,
> Dimitre Novatchev.
>
>
>
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