Re: char replacement

You can use the str-map() function from FXSL to replace any occurence
of a character with a given string.

See also the article "Two-stage recursive algorithms in XSLT" by
Slawomir Tyszko and Dimitre Novatchev at:

http://www.topxml.com/xsl/articles/recurse/default.asp

It describes a combination of a divide and conquer (DVC) and straight
recursion over lists as the optimal when used on large input with XSLT
processors, which do not implement tail recursion efficiently.

Cheers,
Dimitre Novatchev.
 

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Philippe
> Figon
> Sent: Thursday, 9 May 2002 2:19 PM
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  char replacement
>
>
> Hellolinefeed
>
> I am trying to write a stylesheet that could replace all the
> carriage return
> (CR) characters (Unicode 'xD') in the text() node of an element with
> something else.
> Let's put it simple ! I have an element named 'screen' with some
> text within
> and I'd wish to put something like ~\\ at the end of each line
(LaTeXing
> isn't it ?):
> <screen>
> agdh djdjdkk
> whjjd kdopd
> shdm gfjkmd
> hdjdj kkdddl
> </screen>
>
> should become :
>
>
> agdh djdjdkk~\\
> whjjd kdopd~\\
> shdm gfjkmd~\\
> hdjdj kkdddl~\\
>
> I wrote a stylesheet like this :
> (the output method is 'text')
>
> <xsl:template match="screen">
>     <xsl:variable name="texto"><xsl:value-of
> select="substring-before(.,xD)"/></xsl:variable>
>   <xsl:value-of select="concat($texto,'~\\')"/>
> </xsl:template>
>
> That works for the first 'xD' appearing but I can't find how to
> make it work
> recursively for the whole content of the 'screen' text. (XSLT is
> not the best
> thing to make strings replacements, I guess ;-) )
>
> Could anyone help ?

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