Re: Parsing a List

Excellent Joreg......thanks a million.

Any idea how I can get the "next 50" and "previous 50" links to work.

Thanks again
ken

>
>

mail from Joerg Heinicke

Hello Kenneth,

you can pass parameters to the stylesheet. In your case for example the
number of the first element to show in the list:

<xsl:param name="first" select="1"/>
<xsl:param name="count" select="50"/>

 > <xsl:template match="DATALIST">
 > <table cellpadding="5" cellspacing="0" border="0">
 > <tr>
 >   <td width="135"><u><font color="green">Company</font></u></td>
 >   <td width="330"><u><font color="green">Address </font></u></td>
 >   <td width="100"><u><font color="green">Phone </font></u></td>
 > <td width="100"></td>
 > </tr>
 >   <xsl:apply-templates select="customer"/>

changed to:
<xsl:apply-templates select="customer[position() >= $first][position()
&lt;= $count]"/>

 > </table>
 > </xsl:template>

<xsl:template match="customer">

<tr>
<td valign="top"><a><xsl:attribute name="href">
adminViewCompanyByID?companyid=<xsl:value-of select="id"/>

&#38;companyname

=<xsl:value-of select="invoicename"/></xsl:attribute><xsl:value-of select

="

invoicename"/></a></td>
<td valign="top"><xsl:value-of select="invoiceaddress"/></td>
<td valign="top"><xsl:value-of select="phone"/></td>
</tr>
</xsl:template>

Simply, all this code does is displays all customers contained in the
database. However my problem is that I have 1000s of customers in the
database and as a result all these are returned in one huge list. My web
page is therefore ridicously wrong.

Does anyone know anyway of displaying say 50 Customers at a time with a
'next' and "previous" link to display  the next or previous 50.

Any help would be greatly appreciated.

Thanks
- ken

Regards,

Joerg

System Development
VIRBUS AG
Fon  +49(0)341-979-7419
Fax  +49(0)341-979-7409
joerg.heinicke@xxxxxxxxx
www.virbus.de