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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: creating list from structured paragraphs
Hi David,
This XSL transformation outputs exactly the same code as you need using
native XML
It uses two templates, 1st matchs <doc> and <para> elements, and the second
transforms all <para-1> into <list-item> simultaneously pasting text part.
XML
----------------------------------------------------
<?xml-stylesheet type="text/xsl" href="xsl.xsl"?>
<doc>
<para>The following text is a list
<para-1>List item No. 1</para-1>
<para-1>List item No. 2</para-1>
<para-1>List item No. 3</para-1>
</para>
</doc>
XSL
----------------------------------------------------
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="xml"/>
<xsl:template match="/">
<doc>
<par>
<xsl:value-of select="par"/>
<xsl:apply-templates/>
</par>
</doc>
</xsl:template>
<xsl:template match="para-1">
<list-item><xsl:value-of select="."/></list-item>
</xsl:template>
</xsl:stylesheet>
-----
Regards, Roman
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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