Re: problem with last() function

> I've had to use "self::node()[position()=last()]" instead of simply 

the step self::node() constructs a current node list with exactly one
element so position() and last() will always be 1, so position()=last()
is always true().

so "self::node()[position()=last()]" is equivalent to self::node()

As you are using this is a boolean context it is true as self::node() is
always non empty, and as | is effectively or-ing together the boolean
values, 
            <xsl:if test="following-sibling::table | 
following-sibling:list | self::node()[position()=last()]">

is equivalent to <xsl:if test="true()">

which is equivalent to ""

I _think_ you want the test to be true just in the case that the only
following nodes (if there are any) are table or list, in which case
that is

<xsl:test="not(following-sibling::node()[not(self::table or self::list)])">

Note if you use node() then all nodes will be tested including any white
space nodes between the elements. If you only want to test following
elements then use * not node()

David

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