RE: container list display problem

Cheers,
Wendell

Hi folks,
Here I go again...
I have included my XSL and XML code if it will help anyone to figure out how I can make this work.
Basically I am having problems with the second line of the test, the code after the *or*. If I replace ../parent with preceding then reel number 5248 frame 485-589 is displayed as if it was the same reel as the previous one, 5249.
thanks for any help you can offer me,
Loren



XSL code
¯-----------------------------------------------------
<!--Creates a variable for testing container values.-->
<xsl:variable name="reelnumber">
<xsl:value-of select="container[@type='reel']"/>
</xsl:variable>
<xsl:choose>
<xsl:when test="(../preceding-sibling::c03[1]/did/container[@type='reel']=$reelnumber)
or (../parent::c02/did/container[@type='reel']=$reelnumber)">

<!--Selects cases where the value of the reel container is the same as that of a previous
component. In that case, no column labels are added and only the frame number appears
along with the other component data.-->

<tr>
<td> </td>
<td valign="top">
<xsl:value-of select="container[@type='frame']"/>
</td>
<td> </td>
<td colspan="7" align="left" valign="top">
<xsl:apply-templates select="unitid"/>

<xsl:text>&#160;</xsl:text>
<xsl:call-template name="unittitle-stuff"/>

<xsl:text>&#160;</xsl:text>
<xsl:apply-templates select="physdesc"/>
<xsl:text>&#160;</xsl:text>
<xsl:apply-templates select="abstract"/>
</td>
</tr>
</xsl:when>


<!--Selects cases where the value of the reel container is not the same as that of a previous
component. In that case, column labels are added and both the reel and frame number appears
along with the other component data.-->
<xsl:otherwise>
<tr>
<td><br /><b>Reel</b></td>
<td><br /><b>Frame</b></td>
</tr>
<tr>
<td valign="top">
<xsl:value-of select="container[@type='reel']"/>
</td>
<td valign="top">
<xsl:value-of select="container[@type='frame']"/>
</td>
<td> </td>
<td colspan="8" align="left" valign="top">
<xsl:apply-templates select="unitid"/>

<xsl:text>&#160;</xsl:text>
<xsl:call-template name="unittitle-stuff"/>

<xsl:text>&#160;</xsl:text>
<xsl:apply-templates select="physdesc"/>
<xsl:text>&#160;</xsl:text>
<xsl:apply-templates select="abstract"/>
</td>
</tr>
</xsl:otherwise>
</xsl:choose>

XML code
¯-------------------------------------------------------

<c02>
<did>
<container type="reel">5248</container>
<container type="frame">22</container>
<unittitle>1st test c02, reel number is 5248
</unittitle>
</did>
</c02>
<c02>
<did>
<container type="reel">5248</container>
<container type="frame">23</container>
<unittitle>same as previous c02, reel number is 5248
</unittitle>
</did>
<c03>
<did>
<container type="reel">5248</container>
<container type="frame">1466-1467</container>
<unittitle>1st test c03, reel number is same as above (5248)
</unittitle>
</did>
</c03>
<c03>
<did>
<container type="reel">5249</container>
<container type="frame">321</container>
<unittitle>c03 level, reel number changes to 5249
</unittitle>
</did>
</c03>
<c03>
<did>
<container type="reel">5249</container>
<container type="frame">322</container>
<unittitle>c03 level and reel number same as above (5249)
</unittitle>
</did>
</c03>
<c03>
<did>
<container type="reel">5248</container>
<container type="frame">485-589</container>
<unittitle>c03 level, reel number changes back to 5248
</unittitle>
</did>
</c03>
<c03>
<did>
<container type="reel">5248</container>
<container type="frame">785</container>
<unittitle>c03 level, same reel number as as above (5248)
</unittitle>
</did>
</c03>
</c02>

>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>The basic problem of your tests using preceding-sibling:: might be
alleviated by shifting to the preceding:: axis. While I know EAD, like Mike
I can't see deeply into your problem without seeing an example of source
code. (As you know there are many ways to do EAD.)

You can test whether the parent of the <did> that houses the <container>
has the same number by going up *two* levels -- "../../@n = @n".

But it sounds like since the tracking of the microfilm reels has no
relation to the XML structure of the source, the preceding:: axis may be a
winner. If you want to check ancestors as well as preceding elements (you
may), check both preceding:: and ancestor:: axes.

Also, problems like yours are often made considerably easier with a
two-pass solution. This is especially the case if there's any sorting
involved (but it sounds like your stuff is already sorted). Even if this
isn't so for you, checking preceding:: can get expensive of processing
cycles (the axis goes all the way back to the start of the document), and
this can be alleviated by running two passes.

For more explicit help, please post a sample of your source (trimmed for
clarity) with the applicable bit of stylesheet.

Regards,
Wendell

At 05:42 PM 5/1/2002, you wrote:
>Michael,
>I am sure I'm doing this wrong as I am a newbie at coding XSL. I am trying
>to find if the parent of the container / the parent of the <did> that
>houses the <container> tag / also has the same container number. So if the
>subseries ends and another series starts, but they are both microfilmed on
>the same reel, then the reel number is not repeated.
>How do I test that in XSL? I tried your suggestion, but unfortunately it
>doesn't solve the problem.
>Thanks very much for responding so quickly. I am really amazed at the
>generosity of people on this list to help even newbies like me.
>Loren
>
>/------------------------------------------------------------
>Date: Wed, 1 May 2002 15:01:55 +0100
>From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx>
>Subject: RE:  container list display problem
>
> > I have been using a style sheet that supports an XML DTD
> > called EAD - Encoded Archival Description. ....
> >aeel">5248</container>
<container
> > <xsl:when test="(../preceding-sibling::c03[1]//did/container
> > @type='reel']=$reelnumber
> > or  parent::c02[last()]/did/container[@type='reel']=$reelnumber)">
> >
>I haven't tried to understand your detailed logic but the
>parent::c02[last()] test looks wrong. A node has exactly one parent so the
>predicate [last()] is always true. You obviously don't want to select the
>"last parent" because there is only one. Perhaps you want to test whether
>the parent is the last child of its own parent? In that case the condition
>would be parent[not(following-sibling::*)].

======================================================================
Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
- ----------------------------------------------------------------------
   Mulberry Technologies: A Consultancy Specializing in SGML and XML
======================================================================

Loren Scherbak
Archives of American Art
Smithsonian Institution
202-275-1687
scherbakl@xxxxxx

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

======================================================================
Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
----------------------------------------------------------------------
  Mulberry Technologies: A Consultancy Specializing in SGML and XML
======================================================================