<xsl:template match="row">
  <xsl:element name="{cell[1]}">
    <xsl:value-of select="cell[2]"/>
  </xsl:element>
</xsl:template>

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of 
> CHAOUI Hassan
> Sent: 26 April 2002 08:11
> To: 'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'
> Subject:  new user xslt
> 
> 
> Hello,
> I'm quite  a new user of this mailing list.
> In my input xml file, I have this structure:
> 
> <table>
>    <row>
>      <cell>
> 	x1
>      </cell>
>      <cell>
> 	y1
>      </cell>
>    </row>
>    <row>
>      <cell>
> 	x2
>      </cell>
>      <cell>
> 	y2
>      </cell>
>    </row>
> </table>
> and I want to transform it to a new xml file witch have this 
> structure:
> 
> <table>
>    <x1>
>      y1
>    </x1>
>    <x2>
>      y2
>    </x2>
> </table>
> 
> thank you for your help.
> 
> 
> 
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