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At 2002-04-28 15:13 -0700, Derek Doerr wrote:
What I want to do is to use XSL to create a table that has one row per class "team". In the first cell, show the team number (the team 'id'). In the second cell, show the names of the students in the team (e.g. "john doe"). You have: <xsl:for-each select="/descendant::student[@id=self::student_id']/child::name"> You have misunderstood the purpose of self:: ... you want current() which will give you the current() node at the beginning of the evaluation of the expression: /descendant::student[@id=current()/student_id]/child::name I'm not sure where you are going with the rest of the template, but the select above should give you what you are looking for. I hope this helps. .................... Ken
G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Box 266, Kars, Ontario CANADA K0A-2E0 +1(613)489-0999 (Fax:-0995) ISBN 0-13-065196-6 Definitive XSLT and XPath ISBN 1-894049-08-X Practical Transformation Using XSLT and XPath ISBN 1-894049-07-1 Practical Formatting Using XSLFO XSL/XML/DSSSL/SGML/OmniMark services, books(electronic, printed), articles, training(instructor-live,Internet-live,web/CD,licensed) Next public training: 2002-05-06,07,09,10,13,20, - 06-04,07,10,11,13,14,17,20,07-31,08-05 XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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