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Hi: furthermore onto this question, how it it is to assign a multiple key? my approach for multiple key is as follows:- <xsl:key name="SortAuthor" match="adventure | sci-fi/star-trek" use="author"/> and the fragment code is as follows: <xsl:for-each select="booklist[generate-id() = generate-id(key('SortAuthor', adventure/author | sci-fi/star-trek/author)[1])]"> <books> <author> <xsl:value-of select="adventure/author | sci-fi/star-trek/author"/> </author> ....more code </books> </xsl:for-each> but it seems it doesnot regonise anything, please can somebody help me out on this one Mank thanks Regards Kit problem,From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Subject: RE: further question regarding the use of Muenchian Method Date: Mon, 15 Apr 2002 20:01:37 +0100 because you can declare multiple <xsl:key> elements with the same name and you effectively get the union of all of them. > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of ªL ¤lªä > Sent: 15 April 2002 18:43 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: further question regarding the use of Muenchian Method > i was wondering whether it is possible to group the content > given that they > belongs to a separate structure (i.e. > <booklist> > <adventure> > <author>author1</author> > <title>1</title> > <adventure> > <adventure> > <author>author2</author> > <title>2</title> > <adventure> > <adventure> > <author>author1</author> > <title>3</title> > <adventure> > <sci-fi> > <star-trek> > <author>author1</author> > <title>6</title> > </star-trek> > <star-trek> > <author>author4</author> > <title>9</title> > </star-trek> > </sci-fi> > </booklist> > > transform to > <booklist> > <books> > <author>author1</author> > <title>1</title> > <title>3</title> > <title>6</title> > </books> > <books> > <author>author2</author> > </title>2</title> > </books> > ...etc > > since there are two different 'forms' of author 'tags' (i am > sure there is > a better description) (i.e adventure/author and > sci-fi/star-trek) i could > not generate the appropiate key for mucheun method (well at > least i am not > certain how) but is there are a way to do so? _________________________________________________________________ MSN ¬Ûï´£¨Ñ±z³Ì²³æªº¤è¦¡¤À¨É¨Ã¦C¦L±zªº¬Û¤ù¡A½Ð²¾¦Ü http://photos.msn.com/support/worldwide.aspx¡C XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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