Re: Contains(@href. '/') returns false

From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>
Reply-To: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>
To: "NILESH PATEL" <jayganesh786@xxxxxxxxxxx>
CC: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  Contains(@href. '/') returns false
Date: Fri, 8 Mar 2002 12:39:32 +0000

Hi Nilesh,

You've forgotten some quotes in your call:

> <xsl:call-template name="lastIndexOf">
>   <xsl:with-param name="string" select="substring-before(@href, '#')" />
>   <xsl:with-param name="char" select="/" />
> </xsl:call-template>

should be:

  <xsl:call-template name="lastIndexOf">
    <xsl:with-param name="string" select="substring-before(@href, '#')" />
    <xsl:with-param name="char" select="'/'" />
  </xsl:call-template>

otherwise you're passing the value of the root node as the $char
parameter.

Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/