Re: XSLT test on the name of a node

> <xsl:variable name="translation" select="$language/node()[local-name() =
@ld-tag]" />

Hello Tim,

I think the problem is in the above code. You are selecting nodes, whose
local name is the same as the value of their ld-tag attribute. What you
probably want to have is current()/@ld-tag:

<xsl:variable name="translation" select="$language/node()[local-name() =
current()/@ld-tag]" />

Furthermore node() is a superset of *. node() = * + text() + comment() +
processing-instruction().

Regards,

Joerg


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