RE: Re: Selecting Maximum Values

Without extensions and resort to sorting, something like this should work:
(considering that the maximum of a list is either the head or the maximum of
the tail of the list)


	<xsl:template name="find-max">
		<xsl:param name="list"/>
		<xsl:choose>
			<xsl:when test="$list">
				<xsl:variable name="head">
					<xsl:value-of select="$list[1]"/>
				</xsl:variable>
				<xsl:variable name="maxTail">
					<xsl:call-template name="find-max">
						<xsl:with-param name="list"
select="$list[position()!=1]"/>
					</xsl:call-template>
				</xsl:variable>
				<xsl:choose>
					<xsl:when test="$head &lt;
$maxTail">
						<xsl:value-of
select="$maxTail"/>
					</xsl:when>
					<xsl:otherwise>
						<xsl:value-of
select="$head"/>
					</xsl:otherwise>
				</xsl:choose>	
			</xsl:when>
			<xsl:otherwise>0</xsl:otherwise>
		</xsl:choose>
	</xsl:template>


-----Original Message-----
From: Dimitre Novatchev [mailto:dnovatchev@xxxxxxxxx]
Sent: Tuesday, 19 March, 2002 08:31
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Re: Selecting Maximum Values


> I was wondering if there was a simplier way, or is this the way to do
> it.  I'm never sure if I'm doing it the "right"
> way. :)

Use the maximum function from FXSL. You can customise it to accept a
comparison function as a parameter -- than you'll have a very flexible
maximum, which is not offered by XSLT 2.0 or any other library.

Cheers,
Dimitre Novatchev




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