RE: Replacing Question

Hey JB,

Here's a pattern based approach:

  <xsl:template match="/">
    <xsl:apply-templates />
  </xsl:template>

  <xsl:template match="Type">
    <xsl:copy>
      <xsl:choose>
        <xsl:when test="Name_of_Data/@Data_Key='test'">
          <xsl:copy>
            <Data>200</Data>
            <xsl:copy-of select="Name_of_Data"/>
          </xsl:copy>
        </xsl:when>
        <xsl:otherwise>
          <xsl:copy-of select="."/>
        </xsl:otherwise>
      </xsl:choose>
    </xsl:copy>
  </xsl:template>


or, to be very specific:

  <xsl:template match="/">
    <xsl:apply-templates select="//Type[Name_of_Data/@Data_Key='test']"/>
  </xsl:template>

  <xsl:template match="Type[Name_of_Data/@Data_Key='test']">
    <xsl:copy>
      <Data>200</Data>
      <xsl:copy-of select="Name_of_Data"/>
    </xsl:copy>
  </xsl:template>


anyway, hope this helps.

-Jeff



-----Original Message-----
From: Joeri Belis [mailto:joeri.belis@xxxxxxxxxxxx]
Sent: Friday, March 15, 2002 8:34 AM
To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Replacing Question


hi, ( I am new to the XSLT env., so this may look trivial to you but no to
me )

This is an XML

<Type>
    <Data>100</Data>
    <Name_of_Data  Data_Key="test"/>
<Type>

How would i replace the data "text" 100 => 200 based on the fact that i want
to search on the name of the data
being the Data_key "test".

The output result should be

<Type>
    <Data>200</Data>
    <Name_of_Data  Data_Key="test"/>
<Type>

Thanks,
JB



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