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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Referencing an element from another XML file
Of course ...
tutorial.xml (which is transformed)
<tutorial>
<author idref="1"/>
</tutorial>
author.xml
<authors>
<author id="1">
<name>foo</name>
</author>
<author id="2">
<name>bar</name>
</author>
</authors>
XSL
<xsl:template match="tutorial">
<xsl:copy>
<xsl:apply-templates select="author"/>
</xsl:copy>
</xsl:template>
<xsl:template match="author">
<xsl:copy>
<xsl:copy-of select="document('author.xml')/authors/author[@id =
current()/@idref]/name"/>
</xsl:copy>
</xsl:template>
output should be
<tutorial>
<author>
<name>foo</author>
</author>
</tutorial>
Of course there are some simplifications:
1. You could store the author.xml in a variable, if you have to use it
often:
<xsl:variable name="authors" select="document('author.xml')/authors/>
Later:
<xsl:copy-of select="$authors/author[@id = current()/@idref]/name"/>
2. You can create a key for the authors:
<xsl:key name="authors" match="author" use="@id"/>
later:
<xsl:copy-of select="key('authors', @idref)"/>
3. If you have a DTD in author.xml setting @id to type ID, you can use the
simple id(). Then you only have to switch to the other file.
<xsl:for-each select="$author">
<xsl:copy-of select="id(@idref)"/>
</xsl:for-each>
Hope this helps,
Joerg
> G'Day People !
>
> My Current Structure (Tutorial.xml)
> ===================================
> <Tutorial>
> <LotsOfOtherElements>
> </LotsOfOtherElements>
>
> <AuthorList>
> <Author>
> <NAME>A</NAME>
> <EMAIL>A@xxx</EMAIL>
> </Author>
> <Author>
> <NAME>B</NAME>
> <EMAIL>B@xxx</EMAIL>
> </Author>
> </AuthorList>
> </Tutorial>
> ===================================
>
> What I wish to do:
>
> I want to have two files:
>
> Tutorial.xml, and
> Author.xml
>
> Then, I want to be able to reference an author existing in author.xml
> >from tutorial.xml.
>
> Is it possible to do something like this ?
>
>
> TIA,
>
> Kunal
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