Re: SORT

Kim,

It looks like your time id's contain all the information you need, in the 
proper format for sorting.  If you just for-each through your <time> 
elements and sort on the id's, you'll have what you want.  No need for any 
special date/time functions.

--jeff


On 5 Mar 2002, Kim Durand wrote:

..I have a problem, The XMl looks like this.
..<programs>
..   <time id = 200203040456>
.. 	<timetext>04:56</timetext>
..  </time>
..
..<time id = 2002030632>
.. 	<timetext>06:32</timetext>
..  </time>
..
..<time id = 200203041156>
.. 	<timetext>11:56</timetext>
..  </time>
..
..<time id = 200203040146>
.. 	<timetext>01:46</timetext>
..  </time>
..
..<time id = 200203041856>
.. 	<timetext>06:56</timetext>
..  </time>
..
..<time id = 200203040256>
.. 	<timetext>02:56</timetext>
..  </time>
..
..<time id = 200203021456>
.. 	<timetext>09:56</timetext>
..  </time>
..</programs>
..
..My problem is to sort out the times in the increasing order. The 
..id in the xml file is arranged in the fashion 
..yyyymmddHH(hrs)MM(mnts).I can get the HH from 
..substring(./time/@id,9,2). and this is what i want to sort in 
..ascending order.
..so that i may show the timetext in chronological order. How do i 
..do this. Can someone help??
..Many Thanks
..
.. XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
..


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list