Re: white space with word wrapping

Hope someone will help!!!

The following is not doing the word wrapping.  When I
pass <cellValue> without the space translation then
the word wrapping take place....

I can't see a reason why it should do word wrapping.
After all, non breaking spaces (the  ) are supposed
to prevent the formatter from breking text there (apart
from this, FOP renders them always as full width space)

BTW as far as i can tell your elaborate text_wrapper and
wrapper_helper construction is actually a no-op. The
purpose of the wrapper_helper template also isn't obvious
to me, you could just call text_wrapper directly.

I suppose you intended to have the wrapper templates
insert spaces or zero width spaces into the output?

<fo:table-cell padding="0.6pt" border="0.5pt solid
black" column-number="1">
<fo:block background-color="#FFFFCC"
color="black" font-size="10pt" text-align="left"
font-family="sans-serif">
<xsl:variable name="cellValue"
select="translate(cell1,' ','&#160;')"/>
<xsl:call-template name="text_wrapper">
<xsl:with-param name="Text" select="$cellValue"/>
</xsl:call-template> </fo:block> </fo:table-cell>


<xsl:template name="text_wrapper">
<xsl:param name="Text"/>
<xsl:choose>
<xsl:when test="string-length($Text)"> <xsl:value-of select="substring($Text,1,30)"/>
<xsl:call-template name="wrapper_helper">
<xsl:with-param name="Text"
select="substring($Text,31)"/> </xsl:call-template>
</xsl:when>
<xsl:otherwise>
</xsl:otherwise>
</xsl:choose>
</xsl:template>

<xsl:template name="wrapper_helper">
<xsl:param name="Text"/>
<xsl:value-of select="substring($Text,1,30)"/> <xsl:call-template name="text_wrapper">
<xsl:with-param name="Text"
select="substring($Text,31)"/>
</xsl:call-template>
</xsl:template>