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hello,
thank you guys, you help a lot. and again, now i have another question and i wonder if there are some solutions for it. i have <memo> <start>$_</start> <end>$_</end> </memo> .. and in the time-table it looks like 1_____2_____3_____4_____5_____6_____7_____8_____9_____10_____11_____12....
|start 2 | |start10 |
|end 4 | |end 12 |
|___________|________________________ |_____________|
|start 3 |
|end 8 |
|_____________________________|
|start 5 |
|end 7 |
|___________|and i want to have them like 1_____2_____3_____4_____5_____6_____7_____8_____9_____10_____11_____12.... |start 2 |start 3 | |start10 | |end 4 |end 8 | |end 12 | |___________|_______________________| |_____________| the colspan of an element whose "start" is less than preceding-element's end is shortened by the "preceding::end 4" - "start 3". if both "start 5" and "end 7" are less than preceding::end(8) then it is skipped.(well, linked in a preceding <memo>'s <td/>) the <memo>s are sorted 1st by <start>, then by <end> , but this time order="descending" it is a table so the space between "end 8" and "start 10" is to be calculated 10-8=2, and putt 2 <td>s between them. At this point i have only the preceding <memo>' "end"(which is = 7), and i have 10-7=3, i.e. 3 <td>s instead of desired 2. The problem is i can not figure out which (double-booked)elements "end" is longest. Of cource there can be a lot of such elements. awaiting for advices, jian _________________________________________________________________ MSN Photos is the easiest way to share and print your photos: http://photos.msn.com/support/worldwide.aspx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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