Re: display parts of XML tree with xsl:copy ?

Thanks a lot for your quick and helpful support.
There is just one question left.

In the moment I get all the volume and number elements incl. text()
even if they issue elem they belong to does not contain any article that
fullfils my condition.

See:
  <issue>
     <volume>17</volume>
     <number>1</number>     <-------------------- this whole <issue> should
not be in output
     <articles />
  </issue>
  <issue>
     <volume>17</volume>
     <number>2</number>
     <articles>
        <article>
         <title>Defining Data Types in a Database Language - A Proposal for
Adding Date and Time Support to SQL.</title>
         <initPage>53</initPage>
         <endPage>76</endPage>
          <authors>
             <author position="00">C. J. Date</author>
          </authors>
        </article>
     </articles>
</issue>
<issue>
...
---
How can I controll that only those ancestors are copied that are in an valid
articles supertree?

----- Original Message -----
From: "Jeni Tennison" <jeni@xxxxxxxxxxxxxxxx>
To: "Robert Sösemann" <robert.soesemann@xxxxxx>
Cc: <XSL-List@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, February 26, 2002 12:09 PM
Subject: Re: [xsl] display parts of XML tree with xsl:copy ?


> Hi Robert,
>
> > From the following article DB (SigmodRecord) i want to e.g. only
> > articles by a certain author but the result tree should still
> > contain the information of <number> which is nearer to the root.
>
> The way I'd approach this kind of filtering problem is to create a
> basic stylesheet that performs the identity transformation (copies
> whatever you get in the source) as follows:
>
> <xsl:transform version="1.0"
>                xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
> <!-- identity template -->
> <xsl:template match="node()|@*">
>   <xsl:copy>
>     <xsl:apply-templates select="@*|node()" />
>   </xsl:copy>
> </xsl:template>
>
> </xsl:transform>
>
> Then, to that identity transform you can add templates that filter out
> portions of the source document. For example, to get basically the
> same thing as the source document, but only include articles that have
> Karen Botnich as an author, I'd use:
>
> <xsl:transform version="1.0"
>                xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
> <!-- identity template -->
> <xsl:template match="node()|@*">
>   <xsl:copy>
>     <xsl:apply-templates select="@*|node()" />
>   </xsl:copy>
> </xsl:template>
>
> <xsl:template match="articles">
>   <articles>
>     <xsl:apply-templates
>       select="article[authors/author = 'Karen Botnich']" />
>   </articles>
> </xsl:template>
>
> </xsl:transform>
>
> Since you want to copy the whole of such articles, you could use
> xsl:copy-of instead:
>
> <xsl:template match="articles">
>   <articles>
>     <xsl:copy-of
>       select="article[authors/author = 'Karen Botnich']" />
>   </articles>
> </xsl:template>
>
> That's likely to be slightly faster.
>
> If you're more comfortable with a pull method, you could use the
> stylesheet instead:
>
> <xsl:transform version="1.0"
>                xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
> <xsl:template match="/">
>   <issues>
>     <xsl:for-each select="/issues/issue">
>       <issue>
>         <xsl:copy-of select="volume | number" />
>         <articles>
>           <xsl:copy-of
>             select="articles/article[authors/author = 'Karen Botnich']" />
>         </articles>
>       </issue>
>     </xsl:for-each>
>   </issues>
> </xsl:template>
>
> </xsl:transform>
>
>
> Cheers,
>
> Jeni
>
> ---
> Jeni Tennison
> http://www.jenitennison.com/
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list