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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Omitting elements from output
Hello Rick, in XSLT there is a built-in template. This gives you the text-value of all nodes, for which you don't have a specific template. You have two possibilities: Either changing <xsl:apply-templates/> to <xsl:apply-templates select="Element1 | Element2"/>. Or you create another for all other nodes, which does not give you the text-value: <xsl:template match="*"/>. Regards, Joerg > I have the follow structure in my stylesheet. > > <xsl:template match="/"> > <xsl:apply-templates/> > <xsl:template> > > <xsl:template match="Element1"> > ... > </xsl:template> > > <xsl:template match="Element2"> > ... > </xsl:template> > > When I transform the XML file, I only want the content of Element1 and > Element2, but the content of the other elements is output as well. How do I > suppress the output of the other elements. Thanks. > > Rick Quatro XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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