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Re: Can I take only parts from node value?
Subject: Re: Can I take only parts from node value?
From: Oleg Tkachenko <olegt@xxxxxxxxxxxxx>
Date: Tue, 19 Feb 2002 18:21:41 +0200
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jp wrote:
<today date="200202190800" />
and I want output:
Time is 08:00
Date is 19.02
Year is 2002
How can I do this with XSL/T? Or should I change XML output?
Use substring(string, start, length?) function.
--
Oleg Tkachenko
Multiconn International, Israel
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
| Current Thread |
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- regd: XSLT in SAXON
- laksh vr - Tue, 19 Feb 2002 08:59:19 -0500 (EST)
- Michael Kay - Tue, 19 Feb 2002 09:22:11 -0500 (EST)
- jp - Tue, 19 Feb 2002 10:55:39 -0500 (EST)
- Robert Koberg - Tue, 19 Feb 2002 11:07:31 -0500 (EST)
- Oleg Tkachenko - Tue, 19 Feb 2002 11:15:51 -0500 (EST) <=
- Michael Kay - Tue, 19 Feb 2002 12:02:39 -0500 (EST)
- jp - Tue, 19 Feb 2002 12:25:05 -0500 (EST)
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