Re: [solved] key with many uses's

Hi Elizabeth,

> Try this:
>
> <xsl:for-each select="$nodes[generate-id(.) =
> generate-id(key('special-phones', string(@description, @paren,
> @description-place))[1])]">

I think you meant concat() rather than string() there? The string()
function can only take one argument. concat() will concatenate
the values of the @description, @paren and @description-place
attributes together into one long string, which will be different for
every combination of @description, @paren and @description-place.

> Why does this work as opposed to
>
> <xsl:for-each select="$nodes[generate-id(.) =
> generate-id(key('special-phones', @description | @paren |
> @description-place)[1])]">

@description | @paren | @description-place creates a node set of (up
to) three nodes - description, paren, and description-place
attributes. When the second argument to key() is a node set, it's
equivalent to calling the key with the string values of each of those
nodes individually, and unioning the results together. In other words:

  key('special-phones', @description | @paren | @description-place)

is roughly equivalent (assuming that all three attributes are present)
to:

  key('special-phones', @description) |
  key('special-phones', @paren) |
  key('special-phones', @description-place)

So what the key returns is a set of nodes that share *any* of the
values of @description, @paren, @description-place with the node
you're looking at (compared to with concat(), where you get those
nodes that share *all* the values). Which is why it doesn't work.
  
Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


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