RE: xsl:copy

Hi

>   I need to generate a copy of an xml file using xsl ...I tried using
> xsl:copy..but this gives me only the value and not the node 
> names ....Is
> there a workaround to accomplish this.

With xsl:copy, this would to it

<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>

but it's easier with xsl:copy-of, i.e.

<xsl:template match="/">
  <xsl:copy-of select=".">
</xsl:template>

Santtu

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