how to work with xml fragment cont'd
Thanks Michael, I tried this but then I need to specify the whole DTD: <!DOCTYPE wrapper [ <!ELEMENT wrapper ANY> <!ELEMENT ....> // all the elements in First.xml <!ENTITY frag SYSTEM "First.xml"> ]> Is there any way how to avoid the need to specify the whole DTD, I don't care about the document type, I just want to include it. br, Jakub "Michael Kay" <michael.h.kay@xxxxxxxxxxxx>@lists.mulberrytech.com on 02/04/2002 11:57:47 AM Please respond to xsl-list@xxxxxxxxxxxxxxxxxxxxxx Sent by: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> cc: Subject: RE: how to work with xml fragment Simplest is to wrap it into a well-formed document: <?xml ...?> <!DOCTYPE wrapper [ <!ENTITY frag SYSTEM "fragment.xml"> ]> <wrapper>&frag;</wrapper> and then supply this wrapper document as input to the XSLT transformation. Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of > Jakub.Valenta@xxxxxxxx > Sent: 04 February 2002 09:32 > To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx > Subject: how to work with xml fragment > > > Hi all, > I have an xml fragment looking like, > <a> > </a> > <a> > </a> > <a> > </a> > > and I would like to process it using XSLT, since it is not valid xml > document (missing root) I don't know how to force the XSLT > engine to work > with it. > Is there any way how to use it either as an input or to get it using > document() function. > > br, > > Jakub > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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