RE: Simple attribute value replacement question

Hi,

You could use:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>

<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>

<xsl:template match="pet">
  <xsl:copy>
    <xsl:attribute name="type">canine</xsl:attribute>
    <xsl:apply-templates/>
  </xsl:copy>
</xsl:template>

</xsl:stylesheet>

Cheers

andrew


===

-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Regina, Paul
Sent: Monday, January 28, 2002 11:40 PM
To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Simple attribute value replacement question


Here is an overly simplified example of what I am trying to do. I want
to convert from one XML to another, I am having trouble changing the
attribute "type". It needs to go from the word "dog" to the word
"canine":

<?xml version="1.0"?>
<petXML>
	<pet type="dog">
		<color>black</color>
	</pet>
</petXML>

To:

<?xml version="1.0"?>
<animalXML>
	<pet type="canine">
		<color>black</color>
	</pet>
</animalXML>

I thought this xsl would do it but apparently not:

<?xml version = "1.0" encoding = "UTF-8"?>
<xsl:transform xmlns:xsl = "http://www.w3.org/1999/XSL/Transform"
version = "1.0">

<xsl:template match = "petXML">
	<xsl:element name = "animalXML">
		<xsl:apply-templates select = "*"/>
	</xsl:element>
</xsl:template>

<xsl:template match = "*">
	<xsl:apply-templates select="@type"/>
	<xsl:copy-of select = "."/>
</xsl:template>

<xsl:template match="@type[.='dog']">
		<xsl:value-of select="canine"/>
</xsl:template>

</xsl:transform>

This is what I get:
<?xml version="1.0"?><animalXML><pet
type="dog"><color>black</color></pet></animalXML>

Can someone please tell me where I am going wrong and how to do this?
Thanks!


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 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list