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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Grouping
 I've been stuck on the next problem for a few days now, eventhough the answer must be real simple ( I think), I cant figure it out. Multiple-level sorting with the pure Muenchian method involves divining a key combination that is unique at each level of the key sort and then recombining this for each node being tested. Personally, I find that sorting sub-groups is a lot easier using variables instead of using key tables. You don't give enough data to write a quick test file, but here is the outline of the code structure: <xsl:variable name="firsts" select="XPath-of-first-level-sort-nodes"/>
<xsl:for-each select="$firsts">
<xsl:if test="generate-id(.)=
generate-id($firsts[XPath-of-unique-value-calculation])">
<!--first-level grouping completed-->
<xsl:variable name="seconds" select="XPath-relative-for-seconds">
<xsl:for-each select="$seconds">
<xsl:if test="generate-id(.)=
generate-id($seconds[XPath-of-unique])">
<!--second-level grouping completed-->
...etc....
</xsl:if>
</xsl:for-each>
</xsl:if>
</xsl:for-each>I hope the above helps. ................... Ken
G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Box 266, Kars, Ontario CANADA K0A-2E0 +1(613)489-0999 (Fax:-0995) ISBN 0-13-065196-6 Definitive XSLT & XPath ISBN 1-894049-08-X Practical Transformation Using XSLT and XPath ISBN 1-894049-07-1 Practical Formatting Using XSLFO XSL/XML/DSSSL/SGML/OmniMark services, books(electronic, printed), articles, training(instructor-live,Internet-live,web/CD,licensed) Next public training: 02-02-11,12,14,15,18,21,03-04,05,06,08,11, - 04-08,09,10,12,05-14,15,06-04,07 XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
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