Subject: Re: arguments for xsl:call-template
From: "Thomas B. Passin" <tpassin@xxxxxxxxxxxx>
Date: Fri, 7 Dec 2001 10:13:00 -0500
|
[Charly]
> Does anyone of you has any idea how to call a template and passing with a
> node as argument.
> I'm trying the following .
>
> <xsl:template name="histogram">
> <xsl:param name="path" />
> <xsl:for-each select="$path">
> <xsl:value-of select="@value"/>
> </xsl:for-each>
> </xsl:template>
>
> <xsl:call-template name="histogram">
> <xsl:with-param name="path" select="'/report/histo/bar'" />
> </xsl:call-template>
>
Just change to one set of quotes in the select attribute and the select will
return a set of nodes, just what you asked for. In other words, your
attribute value as you wrote it is a string (because of the extra set of
quotes), and you want it to be a node-set.
Tom P
> my XML looks like .
> <report>
> <histo>
> <bar value="20" />
> <bar value="30" />
> <bar value="40" />
> <bar value="50" />
> </histo>
>
> </report>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|