RE: xsl:param and replace.xsl

Mike,
This is a dos question
If you do this

saxon authors.xml replace.xsl > newfile.xml

Of course authors.xml remains untouched because the result is in
newfile.xml.
You cant do this

saxon authors.xml replace.xsl > authors.xml

Because dos opens authors.xml for redirecting to before saxon opens it
so it will be empty and saxon will give you an error on the input file.

Error
  java.io.EOFException: no more input
Transformation failed: run-time errors were reported

But you can do this

Saxon -o authors.xml authors.xml replace.xsl

Which will replace authors.xml with the result of the transform.
But as people have said it isn't usualy a good idea to do it but saxon
will not overwrite the output file if there is an error in the transform
;-)

Ciao Chris

XML/XSL Portal
http://www.bayes.co.uk/xml


> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Mike Ferrando
> Sent: 13 December 2001 17:58
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  xsl:param and replace.xsl
> 
> 
> Friends,
> I am trying to process some xml xsl documents from Michael 
> Kay's book on page 518 (authors.xml replace.xsl).
> 
> My objective is to use the xsl stylesheet to replace text in 
> a xml document without creating a new document. But I am 
> getting an error when I type the command at the dos prompt 
> for saxon. The command line is given in the book.
> 
> saxon source.xml replace.xsl replace=author by=***
> 
> The error I get is "Source file source.xml does not exist."
> 
> So, I typed in "authors.xml" for "source.xml" and I get the 
> output in the dos window. I can create a file with it by 
> ">newfile.xml", but the authors.xml file is untouched.
> 
> Anybody know what I am doing wrong?
> 
> Mike F.
> 
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