RE: xsl:variable question

Hello Long!

choose

1. Machine answer: Your second stylesheet is ill-formed because of wrong </template> end-tag, it's probably </xsl:template>.

2.Both stylesheets will not work because of unresolved variable reference in the template named "dosomething".
If you want $mode in the second template, pass it as parameter:
<xsl:template match="/">
	<xsl:variable name="mode">1</xsl:variable>
	<xsl:call-template name="dosomething">
		<xsl:with-param name="mode" select="$mode"/>
	</xsl:call-template>
	......
</xsl:template>
	<xsl:template name="dosomething">
	<xsl:param name="mode"/>
	<xsl:if test="$mode='1'">
		.....
	</xsl:if>
	.....
</xsl:template>

---
Oleg Tkachenko,
Multiconn International, Israel 

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Long Zhao
> Sent: Wednesday, December 19, 2001 11:28 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  xsl:variable question
> 
> 
> hi everyone
> 
> here are two xsl files :
> 
> <xsl:template match="/">
> 	<xsl:variable name="mode">1</xsl:variable>
> 	......
> </xsl:template>
> 
> <xsl:template name="dosomething">
> 	<xsl:if test="$mode='1'">
> 		.....
> 	</xsl:if>
> 	.....
> </template>
> ------------------------------------
> <xsl:template match="/">
> 	<xsl:variable name="mode" select='1'/>
> 	......
> </xsl:template>
> 
> <xsl:template name="dosomething">
> 	<xsl:if test="$mode='1'">
> 		.....
> 	</xsl:if>
> 	.....
> </template>
> 
> why the first one does not work, but the second one works.
> 
> am i doing anything wrong in the first xsl?
> 
> thanks
> 
> Long
> 
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> 


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