RE: for-each order

how about this

<xsl:variable name="position">
   <xsl:for-each select="$path">
      <xsl:value-of select="concat(@value, position)"/>,
   </xsl:for-each>
</xsl:variable>

Long

-----Original Message-----
From: Charly [mailto:cohana@xxxxxxxxxxxxxxx]
Sent: Friday, December 14, 2001 2:35 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  for-each order


Hello,
Is there a way to do <xsl:for-each ..... and looping backwards.

My XML looks like 
<histo>
   <bar value="60" legend="Jan" />
   <bar value="77" legend="Feb" />
   <bar value="53" legend="Mar" />
   <bar value="14" legend="Apr" />
</histo>

and I want to store 14,53,77,60 in a variable .


<xsl:variable name="position">
   <xsl:for-each select="$path">
      <xsl:value-of select="@value"/>,
   </xsl:for-each>
</xsl:variable>



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list