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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] A little question...
Hi to all,
I need to know the filename of the xml being processed by the xslt stylesheet, something like this... The XML doc: (test.xml) ?xml version="1.0"?> <?cocoon-process type="xslt"?> <?xml-stylesheet href="filename.xsl" type="text/xsl"?> . . . The XSLT stylesheet (filename.xsl) <?xml version="1.0" encoding="iso-8859-1"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template match="/"> <xsl:variable name="self"> <?SOME_INSTRUCTION_TO_OBTAIN_XML_FILENAME?> </xsl:variable> The original XML doc: <xsl:value-of select="$self"/> </xsl:template> </xsl:stylesheet> The desidered output: The original XML doc: test.xml Some ideas? Thanks. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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