Re: ancestor query

You can use ancestor like the following one. You only need a common ancestor
of both elements, in your case 'table-header'. I assume, that you need the
@lang too.

1st method (using ancestor):

<xsl:value-of select="concat(.,' ',
ancestor::table-header/table-header-literals/unit[@lang =
current()/@lang])"/>

2nd method (using root node):


<xsl:value-of select="concat(.,' ',
/query-result/yearbook/table-header-literals/unit[@lang =
current()/@lang])"/>

3rd method (using parents):

<xsl:value-of select="concat(.,' ',
../../../table-header-literals/unit[@lang = current()/@lang])"/>

4th method (using keys):

<xsl:stylesheet ....>
<xsl:key name="units" match="unit" use="@lang"/>
<xsl:template match="column-header">
    <xsl:value-of select="concat(.,' ',key('units',@lang))"/>
</xsl:template>
</xsl:stylesheet>

Regards,

Joerg



> I have the following xml:
>
> <query-result>
>    <yearbook id="fzyb" volume="49" year="1999">
> <name lang="CH">English Name...</name>
>                          .....
> <table-header>
> <table-header-literals>
> <literal name="number">22</literal>
>                                         <literal
> name="startpage">57</literal>
> <literal name="table" lang="EN">TABLE</literal>
> ....
> <unit name="fzybk-MT-N" lang="ES">TM N</unit>
> </table-header-literals>
> <table-column-headers>
> <table-column-header-row>
> <column-header lang="AR" name="ELEMENT">Arabic name
> ...</column-header>
> <column-header lang="CN" name="ELEMENT">Chinese name</column-header>
> <column-header lang="EN" name="ELEMENT">PRODUCTION</column-header>
> <column-header lang="FR" name="ELEMENT">PRODUCTION</column-header>
> <column-header lang="ES" name="ELEMENT">PRODUCCION</column-header>
> </table-column-header-row>
> <table-column-header-row>
>                                          .........
>
> My xsl:
>  .........
>  <xsl:for-each
>
select="./table-header/table-column-headers/table-column-header-row/column-h
> eader[@name='ELEMENT']">
>        <xsl:sort select="concat(substring(./@lang='ES',1,1),./@lang)"
> data-type="text" order="ascending"/>
>              <fo:table-cell>
>               <fo:block text-align="center" space-after.optimum="5pt"
> font-weight="bold" space-before.optimum="10pt">
>                  <xsl:value-of select="concat(.,' ', '<<unit
details>>')"/>
>               </fo:block>
>               </fo:table-cell>
>      </xsl:for-each>
> .........
>
> I want to have the 'unit' node value in the concatenation. Is there a way
> that I can either:
>
> - get to the root path directly then work my way down to the node.
>
> e.g. root/query-result/yearbook/table-header/table-header-literals/unit
>
> - or go up the node tree, by making use of ancestor (I have had trouble
with
> this).
>
> Thanks
>
> Tanz


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list