Sorting out doublettes...

Hello all,

I have an XML file and want to convert it to another XML file.

The basic source XML is (simplified):

<root>
<Product>
 <ID value="someuniquevalue1"></ID>
 <accessory/>
</Product>
<Product>
 <ID value="someuniquevalue2"></ID>
 <accessory>
  <Product>
   <ID value="someuniquevalue1"></ID>
   <accessory/>
  </Product>
 </accessory>
</Product>
<Product>
 <ID value="someuniquevalue3"></ID>
 <accessory/>
</Product>
<Product>
 <ID value="someuniquevalue4"></ID>
 <accessory>
  <Product>
   <ID value="someuniquevalue5"></ID>
   <accessory/>
  </Product>
 </accessory>
</Product>
</root>

That is, a product CAN contain an accessory, which is in itself a product.
This is not recursive. Products can also be both an accessory AND a
standalone product, which means they appear twice in the source, once as a
standalone, once in an accessory section of another product. It's also
possible that a product appears ONLY in the accessory section.

I want to grab all products and accessories exactly once and do some
transformations on them. Sadly I fail to filter the doublettes. This is how
I grab the Products:

  <xsl:apply-templates select="*[not(parent::accessory)]/Product"/>

(getting all products that are not accessories)

Then I do

  <xsl:apply-templates select="//accessory/Product"/>

(getting all accessories)

How can I sort out all doublettes? Must I take another approach?

Changing the source XML is not an option unfortunately.

Thanks for your help,
Christian

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