RE: sorting problem

> I don't understand the question.
> 
> 
> After this:
> 
>     <xsl:for-each select="r">
> 
> you are only hgoing to get each r element once.

There are 12800 r elements.

> 
> so what is "a" here and why does it appear twice?

is the contents of the <termX> element.

I eventually resolved it with
 <xsl:sort select="m655/*[last()]"/>
 
which I was quite surprised to find worked!

The functionality is to sort by bubbling up lower numbers,
giving a level sort which might be depicted as
  term10 term4 term3
  term 9 term8 term7
  term 3 term 2

This would be the case for successive part records of

<r>
   ..
  <m655>
    <tag>
    <term1>
     ...
    <term10>

<r>
   ..
  <m655>
    <tag>
    ...
    <term3>
    <term4>
 
etc.


I.e. it sorted on the last one, irrespective of what 'number'
was present for X in termX.



I'm nearly there, just need to find out how to do it for
lower level groupings.


Regards DaveP

- 

NOTICE: The information contained in this email and any attachments is 
confidential and may be legally privileged. If you are not the 
intended recipient you are hereby notified that you must not use, 
disclose, distribute, copy, print or rely on this email's content. If 
you are not the intended recipient, please notify the sender 
immediately and then delete the email and any attachments from your 
system.

RNIB has made strenuous efforts to ensure that emails and any 
attachments generated by its staff are free from viruses. However, it 
cannot accept any responsibility for any viruses which are 
transmitted. We therefore recommend you scan all attachments.

Please note that the statements and views expressed in this email 
and any attachments are those of the author and do not necessarily 
represent those of RNIB.

RNIB Registered Charity Number: 226227

Website: http://www.rnib.org.uk 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list