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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] AW: Getting at original document from inside document(
One way would be to store root of original document in a variable.
Like:
<xsl:variable name="original" select="/" />
This should work.
- Manfred
> -----Ursprüngliche Nachricht-----
> Von: Phil Endecott [SMTP:spam-from-xsl-list@xxxxxxxxxxxx]
> Gesendet am: Dienstag, 23. Oktober 2001 15:25
> An: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Betreff: Getting at original document from inside document()
>
> Dear XSL experts,
>
> Once I am in a document selected by a document() function, is there
> any way to refer to nodes in the original source document?
>
> Here's a (contrived) example: I have this as my main source document:
>
> <book title="foo">
> <chapter src="chap1.xml"/>
> </book>
>
> Then I have a stylesheet that does something like:
>
> <xsl:template match="chapter">
> <xsl:apply-templates select="document(@src)/*"/>
> </xsl:template>
>
> and then somewhere deep in the processing of the chapter's contents I
> want to use the book's title. At first I naively tried /book/@title -
> but that doesn't work, because / is the root of chap1.xml, not of the
> source document. I could use document('....')/book/@title, if I knew
> what the name of the original source file was: but I don't.
>
> I was hoping that something like document('')/book/@title would get
> the answer, but it looks like this gets the stylesheet, not the
> original input document.
>
> Of course there are various hacks to get or fix the filename that
> could have the desired effect, but I was hoping that someone would
> know of a "clean" way to do this.
>
> Any ideas anyone?
>
> Maybe there is a case for adding something to the next XSL to do this?
>
> Thanks,
>
> --Phil.
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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