To display the output depending upon condition

I have the following XML:

<Sections>
	<Messages>
		<Message dbMessageId="927"  parentId="0">third
message</Message>
		<Message dbMessageId="910" parentId="0">first
title</Message>
		<Message dbMessageId="911" parentId="910">reply to
first title</Message>
		<Message dbMessageId="928" parentId="0">fourth
title</Message>
		<Message dbMessageId="929" parentId="928">reply to
fourth title</Message>
	</Messages>
</Sections>

I have the following XSL to display this XML:
<?xml version="1.0" ?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">

<xsl:output method="xml" encoding="iso-8859-1"/>
<xsl:strip-space elements="*"/>

<xsl:template match="*|text()|@*">
	<xsl:copy>
		<xsl:apply-templates select="@*"/>
		<xsl:apply-templates/>
	</xsl:copy>
</xsl:template>

<xsl:template match="Sections">
	<xsl:apply-templates select="Messages" />
</xsl:template>


<xsl:template match="Messages">
	<xsl:apply-templates select="Message[@parentId=0]"/>
</xsl:template>

<xsl:template match="Message">
	<xsl:variable name="messageId"><xsl:value-of
select="@dbMessageId"/></xsl:variable>
	<xsl:apply-templates
select="../Message[@parentId=$messageId]"/>
</xsl:template>

</xsl:stylesheet>


This is working fine and good.

But What I need is:

1.   Now the grouping starts with parentId=0 and then 
     grouping all the child with them.

2.   At this point I need to check whether that 
     particular parentId !=0 and if yes I need to 
     display that message as a particular left not a 
     part of tree.

3.   The reason for this query was if I do a search
     via my web interface I might get some data whose
     parentId !=0, since this XSL starts with 
     parentId=0, I AM NOT GETTING THAT TREE AT ALL.

Please help me to solve this problem.

Many Thanks
Srini


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