<xsl:template match="a|c">
  <xsl:copy>
    <xsl:apply-templates/>
  </xsl:copy>
</xsl:template>

<xsl:template match="b">
  <x>
    <xsl:apply-templates/>
    <m></m>
    <n></n>
  </x>
</xsl:template>

but if want to replace node b with node z ie

<a>
	<b>
		<c></c>
	</b>
</a>

is changed to
<a>
	<x>
		<c></c>
		<m></m>
		<n></n>
	<x>
</a>

I can achive this by simply deleting node b and its chilren and adding node
x.
Is there any other way around this?

mihir
-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Manu KY
Sent: Thursday, October 04, 2001 2:09 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  questions.

Hi,
write xsl:template match = "b"

Manu

hi,
I have a xml file in the form

<a>
       <b>
               <c></c>
       </b>
</a>

I want to add two more children to node b say m and n so that the

resultant

xml looks like this.....

<a>
       <b>
               <c></c>
               <m></m>
               <n></n>
       </b>
</a>

BUT in the xsl file in want to specify the path with respect to node b.
How do i do it?
mihir

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