Position of a Child
Hi all, I'm having problems getting the child's position() of the context node. I reference the child by its name (stored in a variable), like this: <xsl:value-of select="*[name()=$NodeName]"/> What I would like to get is the position of that child inside the context node. I don't seem to find the correct syntax for this. Thanks in advance, Frank. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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