Thanks, I understand it and think it will work
only downside is it requires hard coding the global variable in xsl file
which I don't really want to.

John

-----Original Message-----
From: Michael Kay [mailto:mhkay@xxxxxxxxxxxx]
Sent: Tuesday, September 18, 2001 5:13 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  how do I pass two xml document into a xsl in java


With most processors you can pass a document as the value of a stylesheet
parameter, though I don't think this is defined in JAXP.

What you can do, though, is to make your calling application implement the
URIResolver interface; nominate this class as your URIResolver; in your
stylesheet have a global variable

<xsl:variable name="doc2" select="document('my:doc2')"/>

and in your resolve() method, return the relevant Source object if the
requested URI is "my:doc2", (and return null otherwise).

Mike Kay

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of
> john.li@xxxxxxxxx
> Sent: 18 September 2001 22:00
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  how do I pass two xml document into a xsl in java
>
>
> Hi, xsl and java gurus,
>
> I use javax.xml.transform.Transformer.transform method to
> transform one xml
> file, now my xsl file needs to transform two xml files.  The
> problem is the
> transform method takes only one Source object only. I don't
> want to have to
> save the java xml document to files and have the xsl file to
> read from the
> files because it will slow down the app.
>
> Any solution to how I can specify two xml documents and
> transform them in
> xsl? and how would xsl refer to these two different sources?
>
> Thanks
> John
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

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