Try <xsl:for-each select="*[not(local-name()='a' or local-name()='b')]">



-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of William Bagby
Sent: Friday, September 07, 2001 8:35 AM
To: XSL Mailing List (E-mail)
Subject:  XPath help


What XPath do I use to specify "elements which are neither <a> nor <b>"?
Here's an example:

<top>
    <a>1</a>
    <a>2</a>
    <a>3</a>
    <b>1</b>
    <b>2</b>
    <c>1</c>
    <c>2</c>
    <c>3</c>
    <c>4</c>
    <c>5</c>
    <d>1</d>
    <d>2</d>
</top>

I would like to iterate over all but the <a> and <b> elements, in this case,
<c> and <d> elements.

Something like this is what I had in mind:

<xsl:template match="top">
    <xsl:for-each select="*[not(a|b)]">
        <!-- do something -->
    </xsl:for-each>
</xsl:template>

But it does not seem to work. I can't find the syntax for this, but it can't
be that hard.  Suggestions?


William Bagby.

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list