On Tue, 4 Sep 2001, Jeroen Janssen wrote:

> Sorry, I made a mistake with the xsl example I sent (apart from the fact
> that it doesn't work :-) stupid me!!
>
> My problem is that I want to take the id from one xml document and I want to
> use that id to load another document, something like this:
>
> <xsl:variable name="path">
>     document('../data/institutions/institutions_country<xsl:value-of
> select="country/@id"/>.xml')/institutions
> </xsl:variable>
>
> <xsl:apply-templates select="$path"/>

Try
<xsl:variable name="filename"
select="concat('../data/institutions/institutions_country',country/@id)"/>

<xsl:variable name="path" select="document($filename)"/>

<xsl:apply-templates select="$path"/>

You need to declare the variable $path with the select="..." syntax to get
a node-set, not a result tree fragment.

Hope this helps.

--Swen


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