Subject: Newbie question - transforming XHTML to XML
From: Jennifer Wrightsell <jwrightsell@xxxxxxxx>
Date: Fri, 28 Sep 2001 13:49:11 -0700
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Hi,
I've been trying to figure out how to transform an XHTML document to an XML
document using an XSLT style sheet. I'm using a freeware app called
Cooktop, which provides a choice of XSLT processors to use for your
transformation.
What I can't figure out is how/where to specify the name/path of the XSLT
style sheet. I've been told this should be done externally, as opposed to
using a link in the input document. Where do I do this and what syntax
should be used?
The following are exerpts of my XHTML input (test.htm) and xsl stylesheet
(test.xsl). Am I using the correct namespace, etc.?
Input -- test.htm:
<html xmlns:h="http://www.w3.org/1999/xhtml">
<head>
<link rel="stylesheet" type="text/css" href="81Help.css" />
<title>Test transformation</title>
</head>
<body>
<h1>Test transformation</h1>
<p>Text</p>
<p>More stuff</p>
</body>
</html>
XSL style sheet (test.xsl)
<?xml version="1.0"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"
xmlns:h="http://www.w3.org/1999/xhtml">
<xsl:output method="xml"/>
<xsl:template match="title">
<title><xsl:value-of select="."/></title>
</xsl:template>
<xsl:template match="h1">
<heading><xsl:value-of select="."/></heading>
</xsl:template>
<xsl:template match="p">
<para><xsl:value-of select="."/></para>
</xsl:template>
</xsl:stylesheet>
The output (test.xml) should look something like this:
<?xml version='1.0'?>
<title>Test transformation<title>
<heading>Test transformation</heading>
<para>Text</para>
<para>More stuff</para>
Can anyone help? Please respond to me directly as I'm subscribed to the
digest only.
Thanks!
Jennifer
Jennifer Wrightsell
ArcGIS Documentation
Online Help Team
ESRI
(909) 793-2853, ext. 1682
jwrightsell@xxxxxxxx
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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